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<title>HotTubWorks Spa Repair Forum Topic: impeller removal</title>
<link>http://www.hottubworks.com/spa-repair-forum/</link>
<description>HotTubWorks Spa Repair Forum Topic: impeller removal</description>
<language>en</language>
<pubDate>Sun, 21 Mar 2010 23:44:38 +0000</pubDate>

<item>
<title>Mary on "impeller removal"</title>
<link>http://www.hottubworks.com/spa-repair-forum/topic/impeller-removal#post-237</link>
<pubDate>Wed, 02 Sep 2009 10:19:36 +0000</pubDate>
<dc:creator>Mary</dc:creator>
<guid isPermaLink="false">237@http://www.hottubworks.com/spa-repair-forum/</guid>
<description>&#60;p&#62;&#60;a href=&#34;http://www.hottubworks.com/SpaParts/PumpsLanding.php&#34;&#62;Spa pumps&#60;/a&#62; will normally have a right hand thread. So when you remove the back plate on the motor and use a screw driver in the slot you would want to turn the screwdriver to the left and the impeller in the opposite direction. Unfortunately it is not uncommon to break a &#60;a href=&#34;http://www.hottubworks.com/SpaParts/PumpParts.php&#34;&#62;impeller&#60;/a&#62; when trying to remove. You can get rust built up on the shaft and will freeze the impeller onto it.
&#60;/p&#62;</description>
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<item>
<title>Anonymous on "impeller removal"</title>
<link>http://www.hottubworks.com/spa-repair-forum/topic/impeller-removal#post-235</link>
<pubDate>Sun, 30 Aug 2009 14:34:16 +0000</pubDate>
<dc:creator>Anonymous</dc:creator>
<guid isPermaLink="false">235@http://www.hottubworks.com/spa-repair-forum/</guid>
<description>&#60;p&#62;Hi,&#60;br /&#62;
I am looking for information on removing an impeller form my pump motor.  I need to replace the seal and slinger.  My question is is the impeller a rt or lt hand thread  and does anyone have any tricks for getting it off.  I have tried having someone hold a large screwdriver at the one end and using a socket on the impeller formed acorn nut but have been unable to remove it.  I don't want to have to destroy it and buy a new one.&#60;/p&#62;
&#60;p&#62;Thanks for any help&#60;/p&#62;
&#60;p&#62;Mark
&#60;/p&#62;</description>
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